Presidential prediction 2012 (final… stay tuned)
Now that all the polls are in, it’s possible to perform variance minimization, a simple procedure to identify the range of polls that can be us...
Senate: 48 Dem | 52 Rep (range: 47-52)
Control: R+2.9% from toss-up
Generic polling: Tie 0.0%
Control: Tie 0.0%
Harris: 265 EV (239-292, R+0.3% from toss-up)
Moneyball states: President NV PA NC
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Attention geeks: As detailed yesterday, I am pondering how to address the issue of black-swan events. It seems to me that the correct approach is not to assume a larger value for the Meta-analysis standard deviation (MMSD), but to use a distribution that has fatter tails.
I am currently considering using the t-distribution. For instance, the t-distribution for a 2.0-sigma lead and 3 degrees of freedom gives tcdf(2.0,3) = 0.93, a 93% win probability. The normal distribution gives normcdf(2.0,0,1) = 97.7%. (Recall that I very roughly estimated the black-swan frequency as about 8%.)
Under current conditions, the re-elect probability would then be tcdf(3.0/2.2,3) = tcdf(1.36,3) = 87%.
Hello Mr. Wang,
I came across a few interesting pieces on fat-tailed distributions while doing research on bankruptcy models:
http://arxiv.org/pdf/cs/0512022.pdf
http://arxiv.org/pdf/cond-mat/0112484v4.pdf
http://arxiv.org/pdf/1201.2817v1.pdf
http://arxiv.org/pdf/0808.2393.pdf
I also considered the possibility of utilizing the student-t distribution. What are your thoughts?
Matt